Unverified50% confidenceFactExact time
火腿三明治定理断言:在n维空间中,对于任意n个可测的物体,总存在一个(n-1)维的超平面能同时将它们逐一二等分
1
Sources
50%
Confidence
Long-term
Relevance
8/24/2026
First Seen
Sources
Related Entities
Related Claims
UnverifiedJohnson-Lindenstrauss引理指出在n维空间中可以找到指数级于n的近似正交向量集合77% similarUnverified龙曲线的豪斯多夫维度为 2,意味着在无穷迭代极限下能完全填充二维平面区域68% similarUnverifiedBorsuk-Ulam定理表明n维球面到n维欧几里得空间的任何连续映射,必然存在一对对径点被映射到同一点67% similarUnverifiedThe Johnson-Lindenstrauss lemma guarantees that for any ε∈(0,1), as long as the target dimension k≥O(log(n)/ε²), there exists a mapping from high dimensions to k dimensions that preserves all pairwise distances within a factor of (1±ε).65% similarUnverifiedA rigid object in space has 6 degrees of freedom (three translational and three rotational).64% similar
Cite This Claim
Stable URI
https://kongchang.com/claim/793657API
curl https://kongchang.com/api/v1/knowledge/claims/793657MCP
get_claim(id=793657)