[KongchangAI]
Unverified50% confidenceFactExact time

对于长度为 n 的查询词和编辑距离 k,Levenshtein 自动机的状态数约为 O(n×(2k+1)^k),随 k 增大呈指数级上升

1
Sources
50%
Confidence
Long-term
Relevance
8/11/2026
First Seen

Sources

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https://kongchang.com/claim/731177
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curl https://kongchang.com/api/v1/knowledge/claims/731177
MCP
get_claim(id=731177)